For those interested in how to solve it:

Logarithms are pretty much the same as exponents. When using a logarithm, you're asking what power do I have to raise the base to the integral argument.

For example: Log_10(100)
Think of this as Log_10(100) = X
> 10^X = 100
What power do I have to raise 10 to for it to equal 100?
> x = 2 or Log_10(100) = 2
In this case Log_10(100) can simply be written as 2


i in math stands for imaginary numbers (or complex)
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1

If i is raised to any number higher than 4 you can simply divide that power by 4 then simplify the i statement by just using the remainder. For example:

i^25
> i^24 * i^1
24 is divisible by 4 meaning i^24 can be written as i since 24 is a multiple of 4
> 1 * i^1
= i

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Hill-Henry wrote For those interested in how to solve it:

Logarithms are pretty much the same as exponents. When using a logarithm, you're asking what power do I have to raise the base to the integral argument.

For example: Log_10(100)
Think of this as Log_10(100) = X
> 10^X = 100
What power do I have to raise 10 to for it to equal 100?
> x = 2 or Log_10(100) = 2
In this case Log_10(100) can simply be written as 2


i in math stands for imaginary numbers (or complex)
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1

If i is raised to any number higher than 4 you can simply divide that power by 4 then simplify the i statement by just using the remainder. For example:

i^25
> i^24 * i^1
24 is divisible by 4 meaning i^24 can be written as i since 24 is a multiple of 4
> 1 * i^1
= i

---

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Wasn't a difficult problem but they way you worded the question initially made me wonder what on earth you were on about you should have said an angle alpha is (log........) radians what is alpha in degrees.