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Do you think that could be the Reason?

It might be
100.00% (3 votes)
Nah, i dont think so
0.00% (0 votes)

Total Votes: 3

I found out Why Hitsam and Hyena dont work( I think )
Posted:

I found out Why Hitsam and Hyena dont work( I think )Posted:

WCarrow
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I was looking at the coding last night and noticed something
I dont know if anyone else noticed this but i'm pretty sure
that I am the first one



If you look at the coding Next to Luna it says Passkey Right?

Ok then Right under Luna there is Hitsam and Hyena and next

To both of those it says Secrets. So its different Coding Then

Luna. I'm thinking that secrets has to do with something else and

not This. Maybe when they Release More of the Coding it will make sense



Post Below and Tell me what you think

Post Below and Tell me what you think
#2. Posted:
WCarrow
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Anyone???





2020202020
#3. Posted:
DarkB8hoven
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I noticed this last night while I was going through the code as well. I don't know that much about coding but obviously when you spell those words with the landers something must happen. I have read in forums that the characters say certain things when you spell HYENA and HITSAM. I think it ends there though, that is what secret1 and secret2 are, just comments by the characters. I would like to hear what the characters say when you make those two words. Has anybody done this?

Here is the part of the code which looks interesting:

level.passkey = array( "l", "u", "n", "a" );
level.passkey_progress = 0;
level.secret1 = array( "h", "i", "t", "s", "a", "m" );
level.secret1_progress = 0;
level.secret2 = array( "h", "y", "e", "n", "a" );
level.secret2_progress = 0;

if ( letter == level.passkey[ level.passkey_progress ] )
{
level.passkey_progress++;
if ( level.passkey_progress == level.passkey.size )
{
flag_set( "passkey_confirmed" );
}
}
else
{
level.passkey_progress = 0;
}
if ( letter == level.secret1[ level.secret1_progress ] )
{
level.secret1_progress++;
if ( level.secret1_progress == level.secret1.size )
{
}
}
else
{
level.secret1_progress = 0;
}
if ( letter == level.secret2[ level.secret2_progress ] )
{
level.secret2_progress++;
if ( level.secret2_progress == level.secret2.size )
{
}
}
else
{
level.secret2_progress = 0;


somebody one youtube has a theory:

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