-w csc(4 x)+x+1

Did I win?

any number between -infinity through infinity

ACoupleTrees wrote any number between -infinity through infinity

^^^

monster69 wrote is the answer infinty?

If it is I answered it before you so ha

Is it 0?
Hope I got it.

Limit of ((x^3)-(4*x^2)+28*x)/((5*x^3)+(3*x^2)+x-1) w.r.t. x at point -1 (two-sided) = 33/4

Limit of (x-2)/(2-(sqrt(4*(x))-(x^2))) w.r.t. x at point 2 (minus) = 0

Limit of erf(n+1)/erf(n) w.r.t. n at point inf (two-sided) = 1

Limit of ((x^3)-(4*x^2)+28*x)/((5*x^3)+(3*x^2)+x-1) w.r.t. x at point inf (two-sided) = 1/5

Limit of ((x-2)/(2)-(sqrt((4*x)-(x^2)))) w.r.t. x at point 2 (minus) = -2

Limit of (x^2-4)/(x-2) w.r.t. x at point 2 (minus) = 4

Limit of ((x-2)/(2-(sqrt((4*x)-(x^2))))) w.r.t. x at point 2 (minus) = minf

Limit of sin(x)/x w.r.t. x at point inf (two-sided) = 0

Limit of 1/(1+2^(1/x)) w.r.t. x at point 0 (plus) = 0

Limit of sin(x)/x w.r.t. x at point 0 (two-sided) = 1

Limit of ((2*x^3)+7*x-1)/((3*x^4)+(2*x)+5) w.r.t. x at point inf (two-sided) = 0

Limit of (n+1)/n w.r.t. n at point inf (two-sided) = 1

Limit of sin(3*x)/x w.r.t. x at point 0 (two-sided) = 3

Limit of (2+x)^5-32/h w.r.t. x at point 0 (two-sided) = (32*h-32)/h

Limit of sin(x)/x w.r.t. x at point 0 (two-sided) = 1

Limit of ((4*x^3)+(7*x^2)+x)/((3*x^2)-(2*x)+1) w.r.t. x at point inf (minus) = inf

Limit of sin(2*x)*cot(4*x) w.r.t. x at point 0 (plus) = 1/2

Limit of ((4*x^3)+(7*x^2)+x)/((3*x^2)-(2*x)+1) w.r.t. x at point inf (plus) = inf

Limit of ((4*x^3)+(7*x^2)+x)/((3*x^2)-(2*x)+1) w.r.t. x at point inf (minus) = inf

Limit of 2*(n+1)^2/n^2 w.r.t. n at point inf (two-sided) = 2

Limit of (x^3-x^2-x+10)/(x^2+3*x+2) w.r.t. x at point 0 (plus) = 5

Limit of (x^3-x^2-x+10)/(x^2+3*x+2) w.r.t. x at point -2 (plus) = -15

Limit of ((4*x^3)+(2*x^2)+x)/((3*x^2)-(2*x)+1) w.r.t. x at point inf (minus) = inf

Limit of ((4*x^3)-(2*x^2)+x)/((3*x^2)-(2*x)+1) w.r.t. x at point inf (minus) = inf

Limit of ((n+1)*log(n+1))/(n*log(n)) w.r.t. n at point inf (two-sided) = 1

Limit of sin(x)^(cos(x)/sin(x)) w.r.t. x at point 00 (two-sided) = undefined

Limit of sin(x)^(cos(x)/sin(x)) w.r.t. x at point +00 (two-sided) = undefined

Limit of sin(x)^(cos(x)/sin(x)) w.r.t. x at point +00 (minus) = inf

Limit of sin(x)^(cos(x)/sin(x)) w.r.t. x at point +1 (minus) = %e^(cos(1)*log(sin(1))/sin(1))

Limit of sin(x)^(cos(x)/sin(x)) w.r.t. x at point +1 (plus) = %e^(cos(1)*log(sin(1))/sin(1))

Limit of sin(x)^(cos(x)/sin(x)) w.r.t. x at point +0 (plus) = 0

Limit of (sqrt(3+2*x))+(sqrt(x+4))/(3*x^2)-4*x+1 w.r.t. x at point 1 (two-sided) = (4*sqrt(5)-9)/3

Limit of sin(x)/x w.r.t. x at point 0 (two-sided) = 1

Limit of ((sqrt(3+2*x))+(sqrt(x+4)))/(3*x^2)-4*x+1 w.r.t. x at point 1 (two-sided) = (2*sqrt(5)-9)/3

Limit of sin(x)^(cot(x)) w.r.t. x at point +0 (plus) = 0

Limit of ((sqrt(3+2*x))+(sqrt(x+4)))/((3*x^2)-4*x+1) w.r.t. x at point 1 (two-sided) = infinity

Limit of (3+cosx)/tanx/2 w.r.t. x at point 0 (two-sided) = cosx/(2*tanx)+3/(2*tanx)

Limit of ((sqrt(3+2*x))-(sqrt(x+4)))/((3*x^2)-4*x+1) w.r.t. x at point 1 (two-sided) = 1/(4*sqrt(5))

Limit of (sqrt(cos(x))-(cos(x))^(1/3))/(sin(x))^2 w.r.t. x at point 0 (two-sided) = -1/12

Limit of sin(x)^(cot(x)) w.r.t. x at point 0 (plus) = 0

Limit of (3^n*sqrt(n+1))/(3^(n-1)*sqrt(n)) w.r.t. n at point inf (two-sided) = 3

Limit of (3+cosx)/tanx/2 w.r.t. x at point Pi (two-sided) = cosx/(2*tanx)+3/(2*tanx)

Limit of (1-1/x)^x w.r.t. x at point 0 (two-sided) = 1

Limit of sin(x)/x+5*x w.r.t. x at point 0 (two-sided) = 1

Limit of sin(x)/x+5*x w.r.t. x at point 0 (two-sided) = 1

Limit of (1-1/x)^x w.r.t. x at point inf (two-sided) = %e^-1

Limit of (1-1/x)^x w.r.t. x at point 0 (two-sided) = 1

Limit of (1-2/x)^x w.r.t. x at point 0 (two-sided) = 1

Limit of 1/(1+2^(1/x)) w.r.t. x at point 0 (plus) = 0

Limit of (1-(2*sqrt(x))/x)^x w.r.t. x at point 0 (two-sided) = 1
lol this pretty much goes on forever

I google it because im retarded.

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Lol.

I have no idea what that code means.

;)

Approvable wrote blah blah blah

someone all ready posted that

MaGiiKZz wrote i use goolge???

ok you get the rep, even though you just typed it in to google, which i expected everyone to do?

TTG_Yankees wrote Umm...how about you do your own homework? :bigups:

Nuff said lol