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Need some help with php database help!
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Need some help with php database help!Posted:
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So this might be hard to explain but I am currently doing a rental system for my php/database project , here is my problem the picture belows shows a bunch of movies and what I want to do is when I click buy on a certain movie lets just say the jason bourne one I want it to re direct me to a php file which will show me the details of that movie and how many I have in stock,,,
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Pick of database :
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Pick of database :
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#2. Posted:
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The simplest way to go about it would be echo the id as part of a GET parameter to another page within your outputted HTML.
E.g. when you're outputting all of the film information, have something like this:
<a href="film.php?id=1">Jason Bourne</a>
and then, when you click that link, take it to a page where you query for the film information where DVID=1 (your GET parameter). Be sure to use prepared statements for your queries etc. etc. you get the point.
E.g. when you're outputting all of the film information, have something like this:
<a href="film.php?id=1">Jason Bourne</a>
and then, when you click that link, take it to a page where you query for the film information where DVID=1 (your GET parameter). Be sure to use prepared statements for your queries etc. etc. you get the point.
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Okay thanks man will try this repped.
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#4. Posted:
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#5. Posted:
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I assume your PHP file is yoursite.com/movie.php?id=<movie_id>
Suggestion: Use slim framework or laravel to handle your routing system... so it could be yoursite.com/movie/<movie_id>
PHP File:
1. Check to make sure that an ID was provided via GET (isset($_GET['id'])
2. Clean the ID to prevent SQL injections, or use PDO or some ORM (like doctrine).
3. Make a simple select query (select all from DVDs where DVDID = $movie_id... obviously, this is pseudocode )
4. Pass that array to the view page, then display the data.
Suggestion: Use slim framework or laravel to handle your routing system... so it could be yoursite.com/movie/<movie_id>
PHP File:
1. Check to make sure that an ID was provided via GET (isset($_GET['id'])
2. Clean the ID to prevent SQL injections, or use PDO or some ORM (like doctrine).
3. Make a simple select query (select all from DVDs where DVDID = $movie_id... obviously, this is pseudocode )
4. Pass that array to the view page, then display the data.
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#6. Posted:
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If you're using mysqli and it's a web project then I can actually help, if not then you can just stop reading now haha. I'm actually doing this for my university project at the moment so I have the code snippets you need!
Hopefully you're dynamically creating your items from a database like so.
If so, for the 'product.php' page this is how you get only information for the selected item.
And to display that information
Hopefully you're dynamically creating your items from a database like so.
$get_items = mysqli_query($dbconnect, "SELECT * FROM `PRODUCT`");
<a href="product.php?id=<?php echo $item['product_id']; ?>">
If so, for the 'product.php' page this is how you get only information for the selected item.
$id = $_GET['id']; //from the URL
$get_item = mysqli_query($dbconnect, "SELECT * FROM `PRODUCT` WHERE `product_id`={$id}");
$item = mysqli_fetch_array($get_item); //
And to display that information
£<?php echo $item['price']; ?>
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#7. Posted:
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Cyimking wrote I assume your PHP file is yoursite.com/movie.php?id=<movie_id>
Suggestion: Use slim framework or laravel to handle your routing system... so it could be yoursite.com/movie/<movie_id>
PHP File:
1. Check to make sure that an ID was provided via GET (isset($_GET['id'])
2. Clean the ID to prevent SQL injections, or use PDO or some ORM (like doctrine).
3. Make a simple select query (select all from DVDs where DVDID = $movie_id... obviously, this is pseudocode )
4. Pass that array to the view page, then display the data.
Not that it reeeeally matters, but !empty() would be more appropriate than isset().
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#8. Posted:
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7en wroteCyimking wrote I assume your PHP file is yoursite.com/movie.php?id=<movie_id>
Suggestion: Use slim framework or laravel to handle your routing system... so it could be yoursite.com/movie/<movie_id>
PHP File:
1. Check to make sure that an ID was provided via GET (isset($_GET['id'])
2. Clean the ID to prevent SQL injections, or use PDO or some ORM (like doctrine).
3. Make a simple select query (select all from DVDs where DVDID = $movie_id... obviously, this is pseudocode )
4. Pass that array to the view page, then display the data.
Not that it reeeeally matters, but !empty() would be more appropriate than isset().
For those that might be wondering...
!empty() is more strict than isset().
!empty() can't be the following:
While isset() can't be NULL or FALSE
!empty() is more strict than isset().
!empty() can't be the following:
NULL,
"",
"0",
0,
0.0,
FALSE,
array(),
or an empty variable
"",
"0",
0,
0.0,
FALSE,
array(),
or an empty variable
While isset() can't be NULL or FALSE
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